A) 518 nm
B) 1035 nm
C) 325 nm
D) 743 nm
Correct Answer: D
Solution :
\[\frac{1}{\lambda }=\frac{1}{{{\lambda }_{1}}}+\frac{1}{{{\lambda }_{2}}}\] \[\frac{1}{355}=\frac{1}{680}+\frac{1}{{{\lambda }_{2}}}\] \[\frac{1}{{{\lambda }_{2}}}=\frac{680-355}{355\times 680}\] \[\Rightarrow \,\,\,{{\lambda }_{2}}=743\,\,nm\]
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