2. Solved Papers
  3. JEE Main & Advanced

JEE Main & Advanced AIEEE Solved Paper-2011

  • question_answer
    In a face centred cubic lattice, atom A occupies the corner positions and atom B occupies the face centre positions. If one atom of B is missing from one of the face centred points, the formula of the compound is   AIEEE  Solved  Paper-2011

    A) \[{{A}_{2}}{{B}_{5}}\]                                       

    B) \[{{A}_{2}}B\]

    C) \[A{{B}_{2}}\]                                      

    D) \[{{A}_{2}}{{B}_{3}}\]

    Correct Answer: A

    Solution :

                 \[{{Z}_{A}}=\frac{8}{5}\] \[{{Z}_{B}}=\frac{5}{2}\] So formula of compound is \[A{{B}_{5/2}}\] i.e., \[{{A}_{2}}{{B}_{5}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner