A) \[\pi \frac{{{v}^{2}}}{{{g}^{2}}}\]
B) \[\pi \frac{{{v}^{2}}}{g}\]
C) \[\pi \frac{{{v}^{4}}}{{{g}^{2}}}\]
D) \[\frac{\pi }{2}\frac{{{v}^{4}}}{{{g}^{2}}}\]
Correct Answer: C
Solution :
Area \[=\pi {{R}^{2}}_{\max }\] \[{{R}_{\max }}=\frac{{{v}^{2}}\sin {{90}^{o}}}{g}=\frac{{{v}^{2}}}{g}\] \[\Rightarrow \] Area \[=\frac{\pi {{v}^{4}}}{{{g}^{2}}}\]
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