JEE Main & Advanced AIEEE Solved Paper-2011

  • question_answer
    A mass M, attached to a horizontal spring, executes S.H.M. with amplitude \[{{A}_{1}}\]. When the mass M passes through its mean position then a smaller mass m is placed over it and both of them move together with amplitude \[{{A}_{2}}\]. The ratio of\[\left( \frac{{{A}_{1}}}{{{A}_{2}}} \right)\]is   AIEEE  Solved  Paper-2011

    A) \[{{\left( \frac{M+m}{M} \right)}^{1/2}}\]                              

    B) \[\frac{M}{M+m}\]

    C)               \[\frac{M+m}{M}\]                          

    D)              \[{{\left( \frac{M}{M+m} \right)}^{1/2}}\]

    Correct Answer: A

    Solution :

                              At mean position, initial velocity \[={{A}_{1}}{{\omega }_{1}}\] New velocity \[=\frac{M{{A}_{1}}{{\omega }_{1}}}{M+m}\] \[\Rightarrow \,{{A}_{2}}{{\omega }_{2}}=\frac{M{{A}_{1}}{{\omega }_{1}}}{M+m}\] \[\frac{{{A}_{2}}}{{{A}_{1}}}=\left( \frac{M}{M+m} \right)\frac{{{\omega }_{1}}}{{{\omega }_{2}}}\] \[{{\omega }_{1}}=\sqrt{\frac{k}{M}}\] \[{{\omega }_{2}}=\sqrt{\frac{k}{M+m}}\] \[\Rightarrow \,\,\,\frac{{{A}_{2}}}{{{A}_{1}}}\sqrt{\frac{M}{m+M}}\] or \[\frac{{{A}_{1}}}{{{A}_{2}}}\sqrt{\frac{m+M}{M}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner