A) \[3.6\times {{10}^{-3}}m\]
B) \[5.0\times {{10}^{-3}}m\]
C) \[7.5\times {{10}^{-3}}m\]
D) \[9.6\times {{10}^{-3}}m\]
Correct Answer: A
Solution :
\[{{a}_{1}}{{v}_{1}}={{a}_{2}}{{v}_{2}}\] \[{{v}_{2}}^{2}={{v}_{1}}^{2}+2gh\] \[{{v}_{2}}^{2}={{(0.4)}^{2}}+2\times 10\times 0.2\] \[={{(0.4)}^{2}}+4\] \[{{v}_{2}}^{2}=4.61\] \[{{v}_{2}}=\sqrt{4.16}\] \[{{v}_{2}}=2.04\,m/s\] Also, \[{{a}_{1}},{{V}_{1}}={{a}_{2}}{{V}_{2}}\] \[{{d}_{1}}^{2}{{V}_{1}}={{d}_{2}}^{2}{{V}_{2}}\] \[{{d}_{2}}={{d}_{1}}\sqrt{\frac{{{V}_{1}}}{{{V}_{2}}}}\] \[=8\times {{10}^{-3}}\sqrt{\frac{0.4}{2.04}}\] \[=3.54\times {{10}^{-3}}m\]You need to login to perform this action.
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