A) More than 9
B) Less than 3
C) More than 3 but less than 6
D) More than 6 but less than 9
Correct Answer: C
Solution :
\[T=F\times r=40\,t-10\,{{t}^{2}}\] \[\alpha =4\,t-{{t}^{2}}\] \[2{{t}^{2}}-\frac{{{t}^{3}}}{3}=0\] \[\Rightarrow t=6\,\,s\] Also, \[\theta =\frac{2{{t}^{3}}}{3}-\frac{{{t}^{4}}}{12}\] \[=\frac{2\times 6\times 6\times 6}{3}-108\] \[n=\frac{\theta }{2\pi }=5.73\]
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