A) \[-\frac{9Gm}{r}\]
B) Zero
C) \[-\frac{4Gm}{r}\]
D) \[-\frac{6Gm}{r}\]
Correct Answer: A
Solution :
Field is zero at O. \[V=-\frac{GM}{r/3}-\frac{4GM}{2r/3}\] \[=-\frac{9GM}{r}\]You need to login to perform this action.
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