question_answer

  A solution containing 2.675 g of\[COC{{l}_{3}}\]⋅ \[6N{{H}_{3}}\](molar mass\[=267.5\text{ }g\,mo{{l}^{-1}}\]) is passed through a cation exchanger. The chloride ions obtained in solution were treated with excess of\[AgN{{O}_{3}}\]to give 4.78 g of\[AgCl\](molar mass\[=143.5\text{ }g\,mo{{l}^{-1}}\]). The formula of the complex is (At. mass of\[Ag=108\text{ }u\])       AIEEE  Solved  Paper-2010

A) \[[COCl{{(N{{H}_{3}})}_{5}}]C{{l}_{2}}\]

B) \[[CO{{(N{{H}_{3}})}_{6}}]C{{l}_{3}}\]

C) \[[COCl{{(N{{H}_{3}})}_{4}}]Cl\]

D) \[[COC{{l}_{3}}{{(N{{H}_{3}})}_{3}}]\]