JEE Main & Advanced AIEEE Solved Paper-2010

  • question_answer
    The Gibbs energy for the decomposition of \[A{{l}_{2}}{{O}_{3}}\]at\[500{}^\circ C\]is as follows: \[\frac{2}{3}A{{l}_{2}}{{O}_{3}}\to \frac{4}{3}Al+{{O}_{2}},\]                                        \[{{\Delta }_{r}}G=+966\,kJ\,mo{{l}^{-1}}\] The potential difference needed for electrolytic reduction of\[A{{l}_{2}}{{O}_{3}}\]at\[500{}^\circ C\]is at least       AIEEE  Solved  Paper-2010

    A) 5.0 V

    B)                        4.5 V     

    C)        3.0 V     

    D)        2.5 V

    Correct Answer: D

    Solution :

                    \[\Delta G=-nFE\]            \[n=4\] \[966\times {{10}^{3}}=-4\times 96500\times E=2.5V\]


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