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JEE Main & Advanced AIEEE Solved Paper-2010

  • question_answer
      One mole of a symmetrical alkene on ozonolysis gives two moles of an aldehyde having a molecular mass of 44 u. The alkene is-       AIEEE  Solved  Paper-2010

    A) ethene

    B)                        propene                             

    C) 1-butene            

    D)        2-butene

    Correct Answer: D

    Solution :

    Molecular weight \[=44\,\,\therefore \,\,\,[C{{H}_{3}}-CHO]\] \[C{{H}_{3}}-CH=O+O=CH-C{{H}_{3}}\xrightarrow{{}}\] \[C{{H}_{3}}-CH=CH-C{{H}_{3}}\]                 2-butene


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