A) \[5.0\times {{10}^{-8}}g\]
B) \[1.2\times {{10}^{-10}}\]
C) \[1.2\times {{10}^{-9}}g\]
D) \[6.2\times {{10}^{-5}}\]
Correct Answer: C
Solution :
\[{{k}_{sp}}=[A{{g}^{+}}][B{{r}^{-}}]=5\times {{10}^{-13}}\] \[[A{{g}^{+}}]=0.05\,M\] \[[B{{r}^{-}}]=\frac{5\times {{10}^{-13}}}{0.05}={{10}^{-11}}M\] \[[B{{r}^{-}}]=[kBr]\] \[\therefore \]Mass added in \[gms={{10}^{-11}}\times 120\,g\] \[=1.2\times {{10}^{-9}}g\]
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