A) 0
B) 2
C) 7
D) 8
Correct Answer: B
Solution :
\[{{8}^{2n}}{{(62)}^{2n+1}}\] \[\Rightarrow \]\[{{(91)}^{2n}}{{(631)}^{2n+1}}\] \[\Rightarrow \]\[{{(}^{2n}}{{C}_{0}}{{9}^{2n}}{{}^{2n}}{{C}_{1}}{{9}^{2n1}}+\ldots ..{{+}^{2n}}{{C}_{2n}})\] \[-{{(}^{2n+1}}{{C}_{0}}{{63}^{2n+1}}{{}^{2n+1}}{{C}_{1}}{{63}^{2n}}+\ldots .\] \[{{-}^{2n+1}}{{C}_{2n+1}}\] Clearly remainder is ?2?.
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