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JEE Main & Advanced AIEEE Solved Paper-2009

  • question_answer
    Let the line \[\frac{x-2}{3}=\frac{y-1}{-5}=\frac{z+2}{2}\]lie in the plane\[x+3y\alpha z+\beta =0.\]Then \[(\alpha ,\,\,\beta )\] equals     AIEEE  Solved  Paper-2009

    A) (6, - 17)                                

    B) (-6, 7)                   

    C) (5, -15)                 

    D) (-5, 5)

    Correct Answer: B

    Solution :

    \[2+3\times 1\alpha (2)+\beta =0\] \[2\alpha +\beta =5\]                    ... (i) \[3152\alpha =0\] \[2\alpha =12\] \[B=5+12=7\] \[(\alpha ,\beta )\equiv (6,7)\]


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