question_answer

In Cannizzaro reaction given below \[2Ph\text{ }CHO\xrightarrow[{}]{:\overset{\text{O-}}{\mathop{OH}}\,}Ph\text{ }C{{H}_{2}}OH+pHC\overset{\bullet \,\bullet }{\mathop{O_{2}^{\text{O-}}}}\,\] The slowest step is:     AIEEE  Solved  Paper-2009

A) the attack of: \[O{{H}^{}}\]at the carboxyl group

B) the transfer of hydride to the carbonyl group

C) the abstraction of proton from the carboxylic group

D) the deprotonation of\[pH\text{ }C{{H}_{2}}OH\]

Correct Answer: B

Solution :

Proton transfer is rate determining step