The net work done on the gas in the cycle ABCDA is
AIEEE Solved Paper-2009
A) zero
B) 276 R
C) 1076 R
D) 1904 R
Correct Answer: B
Solution :
\[{{W}_{ABCD}}={{W}_{AB}}+{{W}_{BC}}+{{W}_{CD}}+{{W}_{DA}}\] \[{{W}_{BC}}=2\times R\times 500\,ln2\] \[=690\text{ }R\] \[{{W}_{CD}}=2\times R\times (300-500)\] \[=\text{ }400\text{ }R\] \[{{W}_{ABCD}}=400R+690R+(-400R)-414R\] \[=276\text{ }R.\]
You need to login to perform this action.
You will be redirected in
3 sec
