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JEE Main & Advanced AIEEE Solved Paper-2008

  • question_answer
    A body is at rest at \[x=0\]. At \[t=0\], it starts moving in the positive x-direction with a constant acceleration. At the same instant another body passes through \[x=0\] moving in the positive x direction with a constant speed. The position of the first body is given by \[{{x}_{1}}(t)\]after time t and that of the second body by \[{{x}_{2}}(t)\] after the same time interval. Which of the following graphs correctly describes \[({{x}_{1}}-{{x}_{2}})\] as a function of time t?       AIEEE  Solved  Paper-2007

    A)              

    B)

    C)       

    D)       

    Correct Answer: D

    Solution :

                    \[{{x}_{1}}=\frac{1}{2}a{{t}^{2}}\] and \[{{x}_{2}}=vt\]    \[\therefore {{x}_{1}}-{{x}_{2}}=\frac{1}{2}a{{t}^{2}}-vt\] \[\Rightarrow \,{{x}_{12}}=\frac{1}{2}a{{t}^{2}}-vt\] At \[t=x,\,\,{{x}_{12}}=0\] and at any time \[\frac{{{d}^{2}}{{x}_{12}}}{d{{t}^{2}}}>0\]


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