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JEE Main & Advanced AIEEE Solved Paper-2008

  • question_answer
    The equilibrium constants \[{{K}_{{{p}_{1}}}}\] and \[{{K}_{{{p}_{2}}}}\] for the reactions \[X2Y\] and \[ZP+Q\], respectively are in the ratio of 1 : 9. If the degree of dissociation of X and Z be equal then the ratio of total pressures at these equilibria is       AIEEE  Solved  Paper-2007

    A) 1 : 3                       

    B)        1 : 9       

    C)        1 : 36     

    D)        1 : 1

    Correct Answer: C

    Solution :

                    Let initial moles of X and Z taken are ?a? and ?b? respectively.                                 \[X\,\,\,\,\,2Y\]                                                 \[ZP+Q\] Moles at equilibrium \[a(1-\alpha )\] \[2a\,\alpha \] Moles at equilibrium \[b(1-\alpha )\,\,b\,\alpha \] \[b\,\alpha \] \[{{K}_{{{p}_{1}}}}=\frac{{{(2a\alpha )}^{2}}{{P}_{{{T}_{1}}}}}{a(1-\alpha )\,\,a(1+\alpha )}\]                                                                        \[{{K}_{{{p}_{2}}}}=\frac{{{(b\alpha )}^{2}}{{P}_{{{T}_{2}}}}}{b(1-\alpha )\,\,b(1+\alpha )}\] \[\frac{{{K}_{{{p}_{1}}}}}{{{K}_{{{p}_{2}}}}}=\frac{4{{P}_{{{T}_{1}}}}}{{{P}_{{{T}_{2}}}}}=\frac{1}{9}\,\,\,;\,\,\,\frac{{{P}_{{{T}_{1}}}}}{{{P}_{{{T}_{2}}}}}=\frac{1}{36}\].


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