A) \[{{(C{{H}_{3}})}_{2}}CHCl\]
B) \[C{{H}_{3}}Cl\]
C) \[{{({{C}_{2}}{{H}_{5}})}_{2}}CHCl\]
D) \[{{(C{{H}_{3}})}_{3}}CCl\]
Correct Answer: B
Solution :
\[{{S}_{N}}2\] reaction is shown by primary halides more than secondary halides and secondary halides more than tertiary halides.
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