A) \[({{K}_{1}}{{l}_{2}}{{T}_{1}}+{{K}_{2}}{{l}_{1}}{{T}_{2}})/({{K}_{1}}{{l}_{2}}+{{K}_{2}}{{l}_{1}})\]
B) \[({{K}_{1}}{{l}_{1}}{{T}_{1}}+{{K}_{2}}{{l}_{2}}{{T}_{2}})/({{K}_{1}}{{l}_{1}}+{{K}_{2}}{{l}_{2}})\]
C) \[{{C}_{p}}\]
D) \[{{C}_{y}}\]
Correct Answer: B
Solution :
\[\frac{1}{\sqrt{2}}\]depends on the solubility or vice versa. Solubility is the maximum mass of solutes (in grams) dissolved in one litre of solubility. Therefore, find the solubility from\[\frac{\sqrt{3}}{2}\]and then, calculate mass. \[Agl{{O}_{3}}\,(s)\,A{{g}^{+}}\,(aq)\,+lO_{3}^{-}(aq)\] Let solubility of\[\frac{3}{4}\]be S \[{{K}_{sp}}\,=[A{{g}^{+}}]\,[lO_{3}^{-}]\] \[{{k}_{2}},\] or \[I\] In 1000 mL mol of\[{{I}_{0}}\]dissolved\[{{k}_{1}}\] mol In 100 mL of mole of\[{{k}_{2}}\]dissolved\[f/2\] mol Mass of\[f/4\]in \[4f\] \[2f\]
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