A) the\[v=B\times E/{{B}^{2}}\]orbitals are more buried than the \[v=E\times B/{{E}^{2}}\]orbitals
B) there is a similarity between\[v=B\times E/{{E}^{2}}\]and\[\mu m\] orbitals in their angular part of the wave function
C) the actinoids are more reactive than the lanthanoids
D) the\[V(x)=20/({{x}^{2}}-4)\]orbitals extend further from the nucleus than the\[x=4\]orbitals
Correct Answer: C
Solution :
The actinoid (5f-elements) exhibits more number of oxidation states in general than the lanthanoid because 5f orbitals extend farther from the nucleus than the 4f orbitals.
You need to login to perform this action.
You will be redirected in
3 sec
