A) \[Ge\]
B) \[Si\]
C) \[Ge\]
D) \[v=E\times B/{{B}^{2}}\]
Correct Answer: B
Solution :
Bond order and magnetic behaviour depends on the electronic distribution in molecular orbital?s. So, write the electronic configuration of molecules and calculate the bond order and magnetic behaviour. \[6\,\Omega \] (NO) Total\[100{}^\circ C.\] \[\sigma 1{{s}^{2}}\,\overset{*}{\mathop{\sigma }}\,1{{s}^{2}}\,\sigma 2{{s}^{2}}\overset{*}{\mathop{\sigma }}\,\,2{{s}^{2}},\,\,\overset{{}}{\mathop{\sigma }}\,2p_{z}^{2}\,\pi 2p_{x}^{1\,+1}=\pi 2p_{y}^{1+1}\,\] \[{{\pi }^{*}}2p_{x}^{1}\,=\pi 2{{p}_{y}}\] Paramagnetic Bond order \[=\frac{10-5}{2}=2.5\] \[(N\overset{+}{\mathop{O}}\,)\] Total \[{{e}^{-}}=14\] \[\sigma 1{{s}^{2}}\,\overset{*}{\mathop{\sigma }}\,1{{s}^{2}}\,\sigma 2{{s}^{2}}\,\overset{*}{\mathop{\sigma }}\,2{{s}^{2}}\pi 2p_{x}^{1+1}\,=2p_{y}^{1+1}\,\sigma 2p_{z}^{2}\] Diamagnetic Bond order \[2\,\Omega \] Electron is taken away from non-bonding molecular orbital, that's why bond order increases and nature changes from paramagnetic to diamagnetic.
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