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JEE Main & Advanced AIEEE Solved Paper-2007

  • question_answer
    A point mass oscillates along the x-axis according to the law\[{{\log }_{3}}e\].If the acceleration of the particle is written as \[{{\log }_{e}}3\]then       AIEEE  Solved  Paper-2007

    A)  \[f(x)={{\tan }^{-1}}(\sin x+\cos x)\]

    B)    \[(\pi /4,\pi /2)\]

    C)  \[(-\pi /2,\pi /4)\]

    D)  \[(0,\pi /2)\]

    Correct Answer: D

    Solution :

    Given oscillation is \[{{\log }_{3}}e\] Acceleration, \[{{\log }_{e}}3\]                                 \[f(x)={{\tan }^{-1}}(\sin x+\cos x)\] So, amplitude \[(\pi /4,\pi /2)\] and phase angle \[(-\pi /2,\pi /4)\]


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