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JEE Main & Advanced AIEEE Solved Paper-2007

  • question_answer
    The velocity of a particle is\[x\]If its position is\[x\]at\[\frac{{{x}^{2}}}{{{\cos }^{2}}\alpha }-\frac{{{y}^{2}}}{{{\sin }^{2}}\alpha }=1,\]then its displacement after unit time\[\frac{\pi }{4}\]is       AIEEE  Solved  Paper-2007

    A) \[{{v}_{0}}+2g+3f\]    

    B)         \[{{v}_{0}}+g/2+f/3\]

    C)         \[{{v}_{0}}+g+f\]

    D)  \[{{v}_{0}}+g/2+f\]

    Correct Answer: B

    Solution :

    The velocity is given as \[\frac{1}{2}{{\,}^{20}}{{C}_{10}}\] i.e.,        \[^{20}{{C}_{10}}\] \[P(x,\text{ }y)\]              \[|~z+4|\le 3,\] On integrating\[|~z+1|\]                 \[D=\left| \begin{matrix}    1 & 1 & 1  \\    1 & 1+x & 1  \\    1 & 1 & 1+y  \\ \end{matrix} \right|\] \[x\ne 0\]            \[y\ne 0\]


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