A) \[\beta -\]
B) \[{{H}_{2}}O\]
C) \[25{}^\circ C\]
D) \[\Lambda _{C{{H}_{3}}COONa}^{o}=91.0\text{ }S\text{ }c{{m}^{2}}/equiv\]
Correct Answer: B
Solution :
\[\frac{1}{2!}-\frac{1}{3!}+\frac{1}{4!}-.....\] \[=1-1+\frac{1}{2!}-\frac{1}{3!}+\frac{1}{4!}-.....={{e}^{-1}}\]
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