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JEE Main & Advanced AIEEE Solved Paper-2007

  • question_answer
    If one of the lines of\[Si{{X}_{2}}<Ge{{X}_{2}}<Pb{{X}_{2}}<Sn{{X}_{2}}\]is a bisector of the angle between the lines\[Si{{X}_{2}}<Ge{{X}_{2}}<Sn{{X}_{2}}<Pb{{X}_{2}}\]then m is       AIEEE  Solved  Paper-2007

    A)  \[Pb{{X}_{2}}<Sn{{X}_{2}}<Ge{{X}_{2}}<Si{{X}_{2}}\]                    

    B)         \[S{{O}_{2}}\]                  

    C)         \[S{{O}_{3}}\]                  

    D)         2

    Correct Answer: C

    Solution :

    Equation of bisectors of lines\[xy=0\]are \[y=\pm \text{ }x.\] Put\[y=\pm x\,in\,m{{y}^{2}}+(1-{{m}^{2}})xy-m{{x}^{2}}=0,\]we get \[m{{x}^{2}}+(1-{{m}^{2}}){{x}^{2}}-m{{x}^{2}}=0\] \[\Rightarrow \]\[(1-{{m}^{2}}){{x}^{2}}=0\]\[\Rightarrow \]\[m=\pm 1\]


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