question_answer

The alkene formed as a major product in the above elimination reaction is     AIEEE  Solved  Paper-2006

A)                            

B) \[C{{H}_{2}}=C{{H}_{2}}\]            

C)              

D)       

Correct Answer: B

Solution :

There are four \[\beta \]-hydrogen?s, in this quaternary ammonium salt. On heating quaternary ammonium salt gives Hofmann elimination (abstraction of most acidic hydrogen which is\[{{\beta }^{1}}'\]) Hence, major product is\[C{{H}_{2}}=C{{H}_{2}}\] (least subsliuted alkene)