question_answer

The circuit has two oppositely connected ideal diodes in parallel. What is the current flowing in the circuit?     AIEEE  Solved  Paper-2006

A) 1.71 A              

B)        2.00 A   

C)        2.31 A              

D)        1.33A

Correct Answer: B

Solution :

We consider the diodes whether it is forward biased or reversed biased. Now, for a closed circuit (loop), KVL can be applied. In the given circuit, diode\[{{D}_{1}}\]is reverse biased while\[{{D}_{2}}\]is forward biased, so the circuit can be redrawn as (\[\because \]for ideal, diodes, reverse biased means open circuited and forward biased means short circuited) Apply KVL to get current flowing through the circuit \[-12+4i-2i=0\] \[\Rightarrow \]               \[i=\frac{12}{6}=2A\]