A) remain unchanged
B) triple
C) increases by a factor of 4
D) double
Correct Answer: C
Solution :
\[r\propto {{[CO]}^{2}}\] \[r'\propto {{[2CO]}^{2}},r\propto 4{{[CO]}^{2}}\] Hence, \[\frac{r'}{r}=\frac{4{{[CO]}^{2}}}{{{[CO]}^{2}}}\] \[r'=4r\]
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