2. Solved Papers
  3. JEE Main & Advanced

JEE Main & Advanced AIEEE Solved Paper-2006

  • question_answer
    In a Wheatstone?s bridge, three resistances P, Q and R are connected in the three arms and the fourth arm is formed by two resistances\[{{S}_{1}}\]and\[{{S}_{2}}\]connected in parallel. The condition for the bridge to be balanced will be     AIEEE  Solved  Paper-2006

    A) \[\frac{P}{Q}=\frac{2R}{{{S}_{1}}+{{S}_{2}}}\]                    

    B) \[\frac{P}{Q}=\frac{R({{S}_{1}}+{{S}_{2}})}{{{S}_{1}}{{S}_{2}}}\]

    C)        \[\frac{P}{Q}=\frac{R({{S}_{1}}+{{S}_{2}})}{2{{S}_{1}}{{S}_{2}}}\]

    D)        \[\frac{P}{Q}=\frac{R}{{{S}_{1}}+{{S}_{2}}}\]

    Correct Answer: B

    Solution :

    For balanced Wheatstone's bridge, \[\frac{P}{Q}=\frac{R}{S}\] Here\[S={{S}_{1}}||{{S}_{2}}=\frac{{{S}_{1}}{{S}_{2}}}{{{S}_{1}}+{{S}_{2}}}\] \[\Rightarrow \]\[\frac{P}{Q}=\frac{R({{S}_{1}}+{{S}_{2}})}{{{S}_{1}}{{S}_{2}}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner