JEE Main & Advanced AIEEE Solved Paper-2006

  • question_answer
    In a region, steady and uniform electric and magnetic fields are present. These two fields are parallel to each other. A charged particle is released from rest in this region. The path of the particle will be a     AIEEE  Solved  Paper-2006

    A) helix                     

    B)        straight line                       

    C) ellipse                  

    D)        circle

    Correct Answer: B

    Solution :

    Let \[\vec{E}\] and \[\vec{B}\] be along x-axis. When a charged particle is released from rest, it will experience an electric force along the direction of electric field or opposite to the direction of electric field depending on the nature of charge. Due to this force, it acquires some velocity along x-axis. Due to this motion of charge, magnetic force\[(F=qvB\text{ }\sin \theta )\]have zero value because angle between \[\vec{v}\] and \[\vec{B}\] would be either\[0{}^\circ \]or\[180{}^\circ \]. So, only electric force is acting on particle and hence it will move along a straight line.


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