A) \[1.05\times {{10}^{-2}}Wb/{{m}^{2}}\]
B) \[1.05\times {{10}^{-5}}Wb/{{m}^{2}}\]
C) \[1.05\times {{10}^{-3}}Wb/{{m}^{2}}\]
D) \[1.05\times {{10}^{-4}}Wb/{{m}^{2}}\]
Correct Answer: A
Solution :
Magnetic field due to a long solenoid is given by \[B={{\mu }_{0}}ni\] From given data, \[6.28\times {{10}^{-2}}={{\mu }_{0}}\times 200\times {{10}^{2}}\times i\] ...(i) (for 1st solenoid) and \[B={{\mu }_{0}}\times 100\times {{10}^{2}}\times (i/3)\] ...(ii) (for IInd solenoid) Solving Eqs. (i) and (ii). we get \[B\approx 1.05\times {{10}^{-2}}\,Wb/{{m}^{2}}\]
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