A) \[Wb/{{m}^{2}}\]
B) henry (H)
C) \[H/{{m}^{2}}\]
D) Weber (Wb)
Correct Answer: B
Solution :
Magnetic energy stored in an inductor \[=\frac{1}{2}L{{i}^{2}}=\frac{L{{Q}^{2}}}{2{{t}^{2}}}\] (\[L\to \]inductance, \[i\to \]current) Energy has the dimensions\[[M{{L}^{2}}{{T}^{-2}}]\]. Equate the dimensions, we have \[[M{{L}^{2}}{{T}^{-2}}]=(Henry)\times \frac{[{{Q}^{2}}]}{[{{T}^{2}}]}\] \[\Rightarrow \]\[[Henry]=\frac{[M{{L}^{2}}]}{[{{Q}^{2}}]}\]
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