A) \[aa'+cc'=1\]
B) \[\frac{a}{a'}\,+\frac{c}{c'}\,=-1\]
C) \[\frac{a}{a'}\,+\frac{c}{c'}\,=1\]
D) \[aa'+cc'=-1\]
Correct Answer: D
Solution :
Given equations of lines are \[x=ay+b,\text{ }z=cy+d\] and \[x=a'y+b',\text{ }z=c'y+d'\] These equations can be rewritten as \[\frac{x-b}{a}=\frac{y-0}{1}=\frac{z-d}{c}\] and \[\frac{x-b'}{a'}=\frac{y-0}{1}=\frac{z-d'}{c'}\] These lines will perpendicular, if \[aa'+1+cc'=0\]
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