JEE Main & Advanced AIEEE Solved Paper-2006

  • question_answer
    The value of\[\sum\limits_{k=1}^{10}{\left( \sin \frac{2k\pi }{11}+i\cos \frac{2k\pi }{11} \right)}\]is     AIEEE  Solved  Paper-2006

    A) 1             

    B)        -1           

    C)        \[-i\]                     

    D)        \[i\]

    Correct Answer: C

    Solution :

    \[\sum\limits_{k=1}^{10}{\left( \sin \frac{2k\pi }{11}+i\cos \frac{2k\pi }{11} \right)}\] \[=i\sum\limits_{k=1}^{10}{\left( \cos \frac{2k\pi }{11}+i\sin \frac{2k\pi }{11} \right)}\] \[=i\,\sum\limits_{k=1}^{10}{\left( {{e}^{-\frac{2k\pi }{11}}} \right)}\] \[=i\,\left\{ \sum\limits_{k=0}^{10}{\left( {{e}^{-\frac{2k\pi }{11}}} \right)-1} \right\}\] \[=-i\]


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