A) 759.00 torr
B) 7.60 torr
C) 76.00 torr
D) 752.40 torr
Correct Answer: D
Solution :
\[\frac{{{p}^{o}}-{{p}_{s}}}{{{p}_{s}}}=\frac{n}{N}\Rightarrow \frac{760-{{p}_{s}}}{{{P}_{s}}}=\frac{18/180}{178.2/18}=\frac{0.1}{9.9}\] \[760-{{P}_{s}}=\frac{1}{99}{{P}_{s}}\] \[760\times 99-{{P}_{s}}\times 99={{P}_{s}}\] \[760\times 99=100\,{{P}_{s}}\] \[{{P}_{s}}=\frac{760\times 99}{100}\] \[{{P}_{s}}=752.4\]
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