2. Solved Papers
  3. JEE Main & Advanced

JEE Main & Advanced AIEEE Solved Paper-2005

  • question_answer
    Two solutions of a substance (non electrolyte) are mixed in the following manner. 480 mL of 1.5 M first solution +520 mL of 1.2 M second solution. What is the molarity of the final mixture?     AIEEE  Solved  Paper-2005

    A) 2.70 M

    B)                                        1.344M

    C)        1.50 M                 

    D)        1.20M

    Correct Answer: B

    Solution :

    Total molarity \[=\frac{{{M}_{1}}{{V}_{1}}+{{M}_{2}}{{V}_{2}}}{{{V}_{1}}+{{V}_{2}}}\] \[=\frac{1.5\times 480+1.2\times 520}{480+520}=1.344M\]


You need to login to perform this action.
You will be redirected in 3 sec spinner