JEE Main & Advanced AIEEE Solved Paper-2005

  • question_answer
    If C is the mid-point of AB and P is any point outside AB, then     AIEEE  Solved  Paper-2005

    A) \[PA+PB+PC=0\]

    B) \[PA+PB+2PC=0\]

    C) \[PA+PB=PC\]

    D) PA + PB = 2PC

    Correct Answer: D

    Solution :

    If C is mid-point of AB and P is the origin, then \[PC=\frac{PA+PB}{2}\] Let P be the origin outside of AB and C be mid - point of AB, then \[PC=\frac{PA+PB}{2}\Rightarrow 2PC=PA+PB\]


You need to login to perform this action.
You will be redirected in 3 sec spinner