A) predominantly 2-butyne
B) predominantly 1 ?butene
C) ppredominantly 2-butene
D) equimolar mixture of 1 and 2-butene
Correct Answer: C
Solution :
\[\underset{\begin{smallmatrix} | \\ Br \end{smallmatrix}}{\mathop{C{{H}_{3}}C{{H}_{2}}CHC{{H}_{3}}}}\,\xrightarrow{{}}\underset{\oplus }{\mathop{C{{H}_{3}}C{{H}_{2}}CHC{{H}_{3}}}}\,\xrightarrow[-{{H}^{+}}]{{}}\] \[\underset{\begin{smallmatrix} less\text{ }substituted \\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,II \end{smallmatrix}}{\mathop{C{{H}_{3}}C{{H}_{2}}CH}}\,=C{{H}_{2}}+\underset{\begin{smallmatrix} more\text{ }substituted \\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,I \end{smallmatrix}}{\mathop{C{{H}_{3}}CH=CHC{{H}_{3}}}}\,\] Stability of\[I>II\]hence I is predominant.
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