JEE Main & Advanced AIEEE Solved Paper-2005

  • question_answer
    Reaction of one molecule of\[HBr\]with one molecule of 1, 3-butadiene at\[40{}^\circ C\]gives predominantly     AIEEE  Solved  Paper-2005

    A) 1-bromo-2-butene under kinetically controlled conditions

    B) 3-bromobutene  under   thermodynamically controlled conditions

    C) 1-bromo-2-butene under thermodynamically controlled conditions

    D) 3-bromobutene under kinetically controlled conditions

    Correct Answer: C

    Solution :

    \[C{{H}_{2}}=CHCH=C{{H}_{2}}+HBr\xrightarrow{{}}\]       \[\underset{1,\,\,2-addition\text{ }product}{\mathop{\underset{\begin{smallmatrix}  | \\  Br \end{smallmatrix}}{\mathop{C{{H}_{3}}CHCH}}\,=C{{H}_{2}}+}}\,\underset{\begin{align}   &  \\  &  \\  &  \\  & 1,\text{ }4-addition\text{ }product \\ \end{align}}{\mathop{C{{H}_{3}}CH=CHC{{H}_{2}}Br}}\,\] Addition is through the formation of allylic carbocation. \[\underset{\begin{smallmatrix}  (2{}^\circ \text{ }allylic) \\  (more\text{ }stable) \end{smallmatrix}}{\mathop{C{{H}_{2}}=CH\overset{\oplus }{\mathop{C}}\,HC{{H}_{3}}}}\,\overset{{}}{\longleftrightarrow}\underset{\begin{smallmatrix}  (1{}^\circ \text{ }allylic) \\  (less\text{ }stable) \end{smallmatrix}}{\mathop{C{{H}_{3}}CH=CH\overset{\oplus }{\mathop{C}}\,}}\,{{H}_{2}}\] Under mild conditions (temperature\[\approx -80{}^\circ C\]) kinetic product is the 1, 2-addition product and under vigorous conditions (temperature\[\approx 40{}^\circ \]) thermodynamic product is the 1, 4-addition product. Thus, l-bromo-2-butene is the major product under given condition.


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