A) \[Li<Na<K<Rb\]: Increasing metallic radius
B) \[I<Br<F<Cl\]: Increasing electron gain enthalpy (with negative sign)
C) \[B<C<N<O\]: Increasing first ionization enthalpy
D) \[A{{l}^{3+}}<M{{g}^{2+}}<N{{a}^{+}}<{{F}^{-}}\]: Increasing ionic size
Correct Answer: C
Solution :
Metallic radii increase in a group from top to bottom. Thus,\[Li<Na<K<Rb\]is True Electron gain of enthalpy of\[Cl>F\]and decreases along a group. Thus, \[l<Br<F<Cl\] is true. Ionisation enthalpy increases along a period left to right but due to presence of half-filled orbitals in N, ionisation enthalpy of\[N>0\]. Thus,\[B<C<N<O\]is incorrect. Larger the (-) ve charge, larger the size and larger the (+) ve charge, simaller the size for isoelectronic species Thus,\[A{{l}^{3+}}<M{{g}^{2+}}<\] \[N{{a}^{+}}<{{F}^{-}}\]is true.
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