A) pyridinium chioro-chromate
B) chromic anhydride in glacial acetic acid
C) acidic dichromate
D) acidic permanganate
Correct Answer: B
Solution :
\[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\overset{{{2}^{o}}}{\mathop{CH}}}\,-CH=CH-C{{H}_{3}}\xrightarrow{{}}\] \[C{{H}_{3}}-\underset{\begin{smallmatrix} ||\, \\ O \end{smallmatrix}}{\overset{{}}{\mathop{CH}}}\,-CH=CH-C{{H}_{3}}\] Only suitable reagent is chromic anhydride in glacial acetic acid Pyridinium chloro chromate gives aldehyde. Other two will also effect \[(C=C)\]bond.
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