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JEE Main & Advanced AIEEE Solved Paper-2004

  • question_answer
    \[6.02\times {{10}^{20}}\]molecules of urea are present in  100 mL of its solution. The concentration of urea solution is (Avogadro constant, \[{{N}_{A}}\,=6.02\,\times {{10}^{23}}\,mo{{l}^{-1}}\])

    A) 0.001 M         

    B)        0.01 M 

    C)        0.02 M             

    D)        0.1 M

    Correct Answer: B

    Solution :

    Avogadro's number\[{{N}_{A}}=6.02\times {{10}^{23}}=1\]mole \[\therefore \]\[6.02\times {{10}^{20}}\] molecules      = 0.001 mole in 100 mL (0.1 L solution) \[\therefore \]Molar concentration\[=\frac{mol}{volume\,in\,L}\] \[=\frac{0.001}{0.1}\] \[=0.01\text{ }M\]


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