JEE Main & Advanced AIEEE Solved Paper-2004

  • question_answer
    Among \[A{{l}_{2}}{{O}_{3}},Si{{O}_{2}},{{P}_{2}}{{O}_{3}}\]and \[S{{O}_{2}},\]the correct order of acid strength is

    A) \[S{{O}_{2}}<{{P}_{2}}{{O}_{3}}<Si{{O}_{2}}<A{{l}_{2}}{{O}_{3}}\]

    B) \[Si{{O}_{2}}<S{{O}_{2}}<A{{l}_{2}}{{O}_{3}}<{{P}_{2}}{{O}_{3}}\]

    C) \[A{{l}_{2}}{{O}_{3}}<Si{{O}_{2}}<S{{O}_{2}}<{{P}_{2}}{{O}_{3}}\]

    D) \[A{{l}_{2}}{{O}_{3}}<Si{{O}_{2}}<{{P}_{2}}{{O}_{3}}<S{{O}_{2}}\]

    Correct Answer: D

    Solution :

    While moving along a group from top to bottom acidic nature of oxides decreases and along a period left to right, acidic nature increases.
    \[Al\] \[Si\] \[P\] \[S\]
    \[Z\] 13 14 15 16
    \[A{{l}_{2}}{{O}_{3}}\] \[Si{{O}_{2}}\] \[{{P}_{2}}{{O}_{3}}\] \[S{{O}_{2}}\]
           \[\xrightarrow[Amphpteric\text{ }\,\,\,\,Acidic\,\,\,\,\,\,\,~~Max.\text{ }\,\,\,\,\,\,\,\,acidic]{{}}\]
    Thus,\[A{{l}_{2}}{{O}_{3}}<Si{{O}_{2}}<{{P}_{2}}{{O}_{3}}<S{{O}_{2}}\]


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