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JEE Main & Advanced AIEEE Solved Paper-2004

  • question_answer
    Time taken by a 836 W heater to heat one litre of water from\[10{}^\circ C\]to\[40{}^\circ C\]is

    A) 50s    

    B)                                        100s                      

    C) 150s                      

    D)        200s

    Correct Answer: C

    Solution :

    Let time taken in boiling the water by the heater is t second. Then, \[Q=ms\Delta T\Rightarrow \frac{Pt}{J}ms\Delta T\]      \[(\because Q=W=Pt)\] \[\therefore \] \[\frac{836}{4.2}t=1\times 1000(40-10)\]               \[(1C=4.2J)\] \[\frac{836}{4.2}t=1000\times 30\] \[t=\frac{1000\times 30\times 4.2}{836}=150\,s\]


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