JEE Main & Advanced AIEEE Solved Paper-2004

  • question_answer
    The total energy of a particle, executing simple harmonic motion is

    A) \[\propto x\]

    B) \[\propto \,{{x}^{2}}\]

    C) Independent of\[x.\]

    D) \[\propto {{x}^{1/2}}\] where,\[x\]is the displacement from the mean position.

    Correct Answer: C

    Solution :

    In simple harmonic motion when a particle is displaced to a position from its mean position, then its kinetic energy gets converted into potential energy. Hence, total energy of a particle remains constant or the total energy in simple harmonic motion does not depend on displacement\[x\]. It fact it depends on the amplitude. \[\because \]Total energy in\[SHM=\frac{1}{2}m{{\omega }^{2}}{{A}^{2}}=2{{\pi }^{2}}m{{A}^{2}}\].


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