question_answer

Excess of\[KI\]reacts with\[CuS{{O}_{4}}\]solution and then\[N{{a}_{2}}{{S}_{2}}{{O}_{3}}\]solution is added to it. Which of the statements is incorrect for this reaction?

A) \[C{{u}_{2}}{{l}_{2}}\]is formed

B) \[Cu{{l}_{2}}\]is formed

C) \[N{{a}_{2}}{{S}_{2}}{{O}_{3}}\]is oxidized

D) Evolved\[{{I}_{2}}\]is reduced

Correct Answer: B

Solution :

\[CuS{{O}_{4}}+2Kl\xrightarrow{\,}\,\underset{Unstabnle}{\mathop{Cu{{l}_{2}}+{{K}_{2}}S{{O}_{4}}}}\,\] Thusis not formed.