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JEE Main & Advanced AIEEE Solved Paper-2003

  • question_answer
    When \[C{{H}_{2}}=CH-COOH\] is reduced with \[LiAl{{H}_{4}}\], the compound obtained will be     AIEEE  Solved  Paper-2003

    A) \[C{{H}_{3}}-C{{H}_{2}}-COOH\]

    B)       \[C{{H}_{2}}=CH-C{{H}_{2}}OH\]

    C) \[C{{H}_{3}}-C{{H}_{2}}-C{{H}_{2}}OH\]

    D) \[C{{H}_{3}}-C{{H}_{2}}-CHO\]

    Correct Answer: B

    Solution :

    \[LiAl{{H}_{4}}\] reduces ?COOH to ?\[C{{H}_{2}}OH\] without affecting C = C bond. \[C{{H}_{2}}=CH-COOH\xrightarrow[THF]{LiAl{{H}_{4}}}\]\[C{{H}_{2}}=CH-C{{H}_{2}}OH\]


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