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  3. JEE Main & Advanced

JEE Main & Advanced AIEEE Solved Paper-2003

  • question_answer
    The orbital angular momentum for an electron revolving in an orbit is given by \[\sqrt{l(l+1)}\frac{h}{2\pi }\]. This momentum for an s-electron will be given by

    A) \[+\frac{1}{2}.\,\frac{h}{2\pi }\]           

    B)       zero      

    C) \[\,\frac{h}{2\pi }\]                        

    D)       \[\sqrt{2}\,.\,\frac{h}{2\pi }\]

    Correct Answer: B

    Solution :

                                For s-electron, \[l=0\].              Therefore, orbital angular momentum = 0


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