A) \[C{{r}^{3+}}\] and \[C{{r}_{2}}O_{7}^{2-}\] are formed
B) \[C{{r}_{2}}O_{7}^{2-}\] and \[{{H}_{2}}O\] are formed
C) \[CrO_{4}^{2-}\] is reduced to \[+3\] state of Cr
D) None of the above
Correct Answer: B
Solution :
\[2CrO_{4}^{2-}+2{{H}^{+}}\xrightarrow{{}}C{{r}_{2}}O_{7}^{2-}+{{H}_{2}}O\]
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