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JEE Main & Advanced AIEEE Solved Paper-2003

  • question_answer
    For a cell reaction involving a two-electron change, the standard emf of the cell is found to be \[0.295\] V at \[{{25}^{o}}C\]. The equilibrium constant of the reaction at \[{{25}^{o}}C\] will be     AIEEE  Solved  Paper-2003

    A) \[1\times {{10}^{-10}}\]               

    B)       \[29.5\times {{10}^{-2}}\]                            

    C) 10                                          

    D) \[1\times {{10}^{10}}\]

    Correct Answer: D

    Solution :

                        \[E_{cell}^{o}=\frac{2.303RT}{n\,F}\log \,{{K}_{eq}}\]                     \[0.295=\frac{0.0591}{2}\log \,{{K}_{eq}}\] \[\therefore \]      \[\log \,{{K}_{eq}}=10\] \[\therefore \]  \[{{K}_{eq}}={{10}^{10}}\]


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